AP 2014 MC Reflection + Corrections

Score 32/40

Honestly a 32 out of 40 is fine with me, it barely makes the cutoff for a an 80%. However, I hope that my timing improves and thinking may speed up. Since starting, it took me around two hours to complete the entire thing. For most of the questions I had to use a pen and paper to consider each process, and then really think about it. Seeing how I got a 32/40 with the amount of time I put in, I think that I should really be doing better. I think my main problem is learning to understand large pieces of code(as in putting missing pieces or analyzing certain lines), and I hope that I may focus on that aspect in future tests.

Corrections

I incorrectly chose the floated value instead of the value that fits the integer primitive. The answer 2.333 should be rounded down to 2.

Choice 1(A) would actually work as it returns value 0 from the function seqSearchRecHelper. Choice 2(B) would be the correct answer as if the data does contain the value 5, the function would instead return -1 creating an out of bounds error.

Because of the usage of an enhanced for each loop, there is no need for the method .get does not need to be used making answer choice D wrong. v.getMileage() would be better as it only uses the variable “v” and nothing else, which is the proper way in using an enhanced loop.

My selected answer(D) is incorrect because choice two does not work. Choice two provides data[k + 1] which would create an out of bounds error on the last part of the array. Choice 1 is correct, and therefore choice A would be correct.

Choice D is incorrect as the last value of the array will not be affected by the for loop as the for loop iterates through the length of the loop minus 1. Choice C would be better as it displays the correct final value of 7.

!(!(a != b)) would just be (a != b), not (a==b) which was my selected answer. B would be a better choice because it contains the proper change through DeMorgan’s Law.

Here baboon would actually be inserted at the end of the array list as it begins with the letter ‘b’ and will be added at size-k which is at the end. From there, my order is correct in “bear” following “zebra” etc. I think I had a little trouble understanding the substring and remove commands, and thus need to look at it more in depth.

Here is just a case of remembering the conditionals. This is an infinite loop as the condition k < 4 will never be satisfied. || means or, meaing that either one may work, which I forgot during the exam.